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Discussions & Feed Members (28)
Mayank Pandey profile picture Mayank Pandey profile picture
Mayank Pandey
2 d - çevirmek

Bhai log algebra ka ek question mocks me bohot time le raha tha: 'Agar x + 1/x = 3 hai, to x^5 + 1/x^5 ki value kya hogi?' Direct identity kya hoti hai iski koi batayega please?

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Poulami Mukherjee

1792173069
Bhai dekh iska direct standard formula hota hai: x^5 + 1/x^5 = (x^2 + 1/x^2)(x^3 + 1/x^3) - (x + 1/x) 1. x^2 + 1/x^2 = 3^2 - 2 = 7 2. x^3 + 1/x^3 = 3^3 - 3(3) = 18 3. Ab bas multiply karo: 7 × 18 - 3 = 126 - 3 = 123! 10 second me answer aata hai bhai, yaad rakhna formula.
· 0
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Debasmita Chakraborty

1792173081
Bhai 123 bilkul sahi hai! Ye TCS ka pet question hai CGL Tier 1 me. x^5 + 1/x^5 hamesha (square × cube - linear) hota hai.
· 0
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Ananya Roy

1792173075
Arre wah Tarun bhai, thank you so much! Mai faltu me binomial expansion soch raha tha. Formula copy me note kar liya maine.
· 0
Pallab Maji profile picture Pallab Maji profile picture
Pallab Maji
2 d - çevirmek

CI vs SI ka ek recurring doubt: 'Agar kisi principal pe 10% rate of interest se 3 saal ka CI aur SI ka difference ₹93 hai, to Principal sum kitna hoga?' Iska direct ratio ya formula kya hota hai?

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Abhishek Roy

1792172983
Bhai 3 saal ke CI - SI difference ka direct formula yaad kar lo: Difference = P × (R/10^2 × (3 + R/10 Isme value put karo: 93 = P × (10/10^2 × (3 + 10/10 93 = P × (1/10 × (31/1 93 = P × (31 / 100 Ab 31 se 93 teen baar me cut ho gaya (31 × 3 = 93)! P = 3 × 1000 = ₹3,000! 15 second me answer aa gaya bhai!
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PUJA GHOSH

1792172983
Tree method se bhi kar sakte ho bhai: 10% = 1/10. Let Principal = 10^3 = 1000 units. 3 saal ka difference hota hai 3a + 1 = 3(1 + 1 = 31 units. 31 units = 93, so 1 unit = 3, total Principal = 1000 × 3 = ₹3000.
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Souvik Dutta

1792172983
Dono method bohot tagde hain! Formula yaad na aaye to Tree method sabse safe rehta hai exam hall me.
· 0
Anurag Verma profile picture Anurag Verma profile picture
Anurag Verma
2 d - çevirmek

Bhai log algebra ka ek question mocks me bohot time le raha tha: 'Agar x + 1/x = 3 hai, to x^5 + 1/x^5 ki value kya hogi?' Direct identity kya hoti hai iski koi batayega please?

avatar

Aman Gupta

1792172530
Bhai dekh iska direct standard formula hota hai: x^5 + 1/x^5 = (x^2 + 1/x^2)(x^3 + 1/x^3) - (x + 1/x) 1. x^2 + 1/x^2 = 3^2 - 2 = 7 2. x^3 + 1/x^3 = 3^3 - 3(3) = 18 3. Ab bas multiply karo: 7 × 18 - 3 = 126 - 3 = 123! 10 second me answer aata hai bhai, yaad rakhna formula.
· 0
avatar

Deepak Verma

1792172535
Bhai 123 bilkul sahi hai! Ye TCS ka pet question hai CGL Tier 1 me. x^5 + 1/x^5 hamesha (square × cube - linear) hota hai.
· 0
avatar

Arjun Rathore

1792172539
Arre wah Tarun bhai, thank you so much! Mai faltu me binomial expansion soch raha tha. Formula copy me note kar liya maine.
· 0
Subhadip Dey profile picture Subhadip Dey profile picture
Subhadip Dey
2 d - çevirmek

CI vs SI ka ek recurring doubt: 'Agar kisi principal pe 10% rate of interest se 3 saal ka CI aur SI ka difference ₹93 hai, to Principal sum kitna hoga?' Iska direct ratio ya formula kya hota hai?

avatar

Prateek Kapoor

1792172440
Bhai 3 saal ke CI - SI difference ka direct formula yaad kar lo: Difference = P × (R/10^2 × (3 + R/10 Isme value put karo: 93 = P × (10/10^2 × (3 + 10/10 93 = P × (1/10 × (31/1 93 = P × (31 / 100 Ab 31 se 93 teen baar me cut ho gaya (31 × 3 = 93)! P = 3 × 1000 = ₹3,000! 15 second me answer aa gaya bhai!
· 0
avatar

Divya Reddy

1792172430
Tree method se bhi kar sakte ho bhai: 10% = 1/10. Let Principal = 10^3 = 1000 units. 3 saal ka difference hota hai 3a + 1 = 3(1 + 1 = 31 units. 31 units = 93, so 1 unit = 3, total Principal = 1000 × 3 = ₹3000.
· 0
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Soma Halder

1792172433
Dono method bohot tagde hain! Formula yaad na aaye to Tree method sabse safe rehta hai exam hall me.
· 0
Rohit Srivastava profile picture Rohit Srivastava profile picture
Rohit Srivastava
2 d - çevirmek

Bhai log algebra ka ek question mocks me bohot time le raha tha: 'Agar x + 1/x = 3 hai, to x^5 + 1/x^5 ki value kya hogi?' Direct identity kya hoti hai iski koi batayega please?

avatar

Saurabh Malik

1792171959
Bhai dekh iska direct standard formula hota hai: x^5 + 1/x^5 = (x^2 + 1/x^2)(x^3 + 1/x^3) - (x + 1/x) 1. x^2 + 1/x^2 = 3^2 - 2 = 7 2. x^3 + 1/x^3 = 3^3 - 3(3) = 18 3. Ab bas multiply karo: 7 × 18 - 3 = 126 - 3 = 123! 10 second me answer aata hai bhai, yaad rakhna formula.
· 0
avatar

Gourav Banik

1792171964
Bhai 123 bilkul sahi hai! Ye TCS ka pet question hai CGL Tier 1 me. x^5 + 1/x^5 hamesha (square × cube - linear) hota hai.
· 0
avatar

Amit Jadhav

1792171954
Arre wah Tarun bhai, thank you so much! Mai faltu me binomial expansion soch raha tha. Formula copy me note kar liya maine.
· 0
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