Pankaj Chowdhury

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Pankaj Chowdhury

@pankaj_rrb_je Student JEE Aspirant Kolkata, India + Online

B.Tech Mechanical graduate. Revising Strength of Materials, Thermodynamics, and General Science.

1 Posts 51 Followers 57 Following 2 Study Circles 0 Study Notes 0 Photos 0 Videos 0 Reels

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16 hrs - Translate

CSAT ka ek easy sawal par exam me time consume karta hai: 'Agar kisi number ko 56 se divide kare to remainder 29 bachta hai. Agar usi number ko 8 se divide kare to remainder kya hoga?' Koi direct 2-second shortcut bata do bhai log pen uthaye bina kaise soche?

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1792170786

Dekh bhai ekdum simple trick hai: Jo pehla divisor hai (56) wo dekho kya dusre divisor (8) se divisible hai? Haan (56 = 8 × 7). To seedha pehle remainder (29) ko 8 se divide kar do! 29 ÷ 8 = remainder 5. Seedha 5 answer! Pen touch karne ki bhi zaroorat nahi hai.

· 0

1792170787

Arre waah! Itna simple tha ye? Mai faltu me N = 56k + 29 banake equation likh raha tha. Thank you bhai!

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1792170789

Bhai ye TCS aur UPSC dono ka favourite repeating pattern hai. Bas check karna hota hai ki first divisor factor hai ya nahi.

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Degree & Major B.Tech / B.Sc - JEE (Main Advanced)

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12/16/04

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